-5x^2-10x+94=0

Solution for -5x^2-10x+94=0 equation:

-5x^2-10x+94=0

a = -5; b = -10; c = +94;
Δ = b2-4ac
Δ = -102-4·(-5)·94
Δ = 1980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1980}=\sqrt{36*55}=\sqrt{36}*\sqrt{55}=6\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-6\sqrt{55}}{2*-5}=\frac{10-6\sqrt{55}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+6\sqrt{55}}{2*-5}=\frac{10+6\sqrt{55}}{-10}
$